A normal distribution has a mean of 82 and a standard deviation of 6. Find the z-score for a data value of 61. Round to two decimal places

Respuesta :

Solution

- The solution steps are given below:

[tex]\begin{gathered} \text{ The formula for the Z-score is:} \\ Z=\frac{X-\mu}{\sigma} \\ where, \\ \mu=\text{ Mean} \\ \sigma=\text{ Standard Deviation} \\ X=\text{ The value whose z-score we want to find.} \\ \\ Z=\frac{61-82}{6} \\ \\ Z=-\frac{21}{6}=-3.50\text{ \lparen To 2 decimal places\rparen} \end{gathered}[/tex]

Final Answer

The answer is -3.50