Given:
[tex]\ln (\frac{e^5}{12})[/tex][tex]\ln (\frac{a}{b})=\ln (a)-\ln (b)[/tex]
Then:
[tex]\ln (\frac{e^5}{12})=\ln e^5-\ln 12[/tex]
[tex]\ln a^b=b\ln a[/tex][tex]\begin{gathered} \ln (\frac{e^5}{12})=\ln e^5-\ln 12 \\ =5\ln e-\ln 12 \\ =5(1)-2.4849 \\ =5-2.4849 \\ =2.515 \\ =2.52 \end{gathered}[/tex]
