Given,
The coordinates of the point A, B , C , D , E and F.
[tex]\begin{gathered} A=(-2,-2) \\ B=(0,-6) \\ C=(8,-2) \\ D=(8,3) \\ E=(6,7) \\ F=(6,2) \end{gathered}[/tex]
Required
The area of the figure.
The length of AB is,
[tex]AB=\sqrt{4+16}=\sqrt{20}[/tex]
The length of BC is,
[tex]BC=\sqrt{64+16}=\sqrt{80}[/tex]
The length of CD is 5 units.
The area of the figure is,
[tex]\begin{gathered} Area\text{ =}\sqrt{20}\times\sqrt{80}+5\times2 \\ =\sqrt{1600}+10 \\ =50\text{ unit}^2 \end{gathered}[/tex]
Hence, the area of the figure is 50 square unit.
