Probability Question.
Red (R) = 2 Prob(R) = 2/12 = 1/6
Green (G) = 3 Prob(G) = 3/12 = 1/4
Blue (B) = 3 Prob(B) = 3/12 = 1/4
Yellow (Y) = 1 Prob(Y) = 1/12
Purple (P) = 2 Prob(P) = 2/12 = 1/6
Brown (Br) = 1 Prob(Br) = 1/12
TOTAL = 12
[tex]\text{Probability =}\frac{no\text{ of required outcomes}}{no\text{ of total outcomes}}[/tex]The probability of picking two blue crayons without looking is:
The first crayon being blue is : Prob(first Blue) = 3/12
The second crayon being blue is : Prob( second Blue) = 2/11 , since the first first is no longer in the box, that is, after the first selection of the first blue crayon, we were left with 2 Blue in the box and the total crayon has also dropped to 11 crayons.
[tex]\begin{gathered} \text{Prob(BB) = Prob(first B) }\times\text{ Prob(second B) } \\ \text{ = }\frac{3}{12}\times\frac{2}{11}=\frac{1}{22} \end{gathered}[/tex]Hence, the correct answer is 1/22
