Given
[tex]y=x^2-x-42[/tex]To find the zeros of the function, set y=0 and solve for x. In this case, since the function is a quadratic polynomial, we can use the quadratic formula, as shown below
[tex]\begin{gathered} y=0 \\ \Rightarrow x^2-x-42=0 \\ \Rightarrow x=\frac{1\pm\sqrt{1+4*42}}{2}=\frac{1\pm13}{2} \\ \Rightarrow x=7,-6 \end{gathered}[/tex]Therefore, the answers are x=-6 and x=7. Options E and G