Given the expression:
[tex]\begin{gathered} \\ \\ \text{ (xy}^7)^3\text{ }\div y^{14} \end{gathered}[/tex]
Let's simplify the expression.
To simplify the expression, take the following steps.
Step 1:
Apply the product rule of exponents
[tex]\begin{gathered} \text{ (xy}^7)^3\text{ }\div y^{14} \\ \\ =x^3\text{y}^7^{(3)}\text{ }\div y^{14} \\ \\ =\text{ }x^3\text{y}^{7\ast3}\text{ }\div y^{14} \\ \\ =\text{ }x^3\text{y}^{21}\text{ }\div y^{14} \end{gathered}[/tex]
Step 2:
Since we have the division sign here, we are to subtract to exponents that has the same bases.
Apply the division rule of exponents.
We have:
[tex]\begin{gathered} \text{ }x^3y^{21}\text{ }\div y^{14} \\ \\ x^3y^{21-14} \\ \\ =x^3y^7 \end{gathered}[/tex]
ANSWER:
[tex]x^3y^7[/tex]
