We know that
The total number of ribbons is 34, this can be expressed as x + y +z = 34. Where y represents blue ribbons and x represents white ribbons, and z represents red ribbons.
The blue ribbons awarded was 1 less than the number of white ribbons. This can be expressed as y = x - 1.
The number of red ribbons was 2 more than the number of white ribbons, this can be expressed as z = x + 2.
First, we combine the second and third equations with the first one.
[tex]x+x-1+x+2=34[/tex]Then, we solve for x
[tex]\begin{gathered} 3x+1=34 \\ 3x=34-1 \\ 3x=33 \\ x=\frac{33}{3} \\ x=11 \end{gathered}[/tex]There are 11 white ribbons.
Then, we find y and z.
[tex]\begin{gathered} y=11-1=10 \\ z=11+2=13 \end{gathered}[/tex]There are 10 blue ribbons and 13 red ribbons.