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a bag contains eight red marbles and 8 blue marbles. what are the chances of drawing a red marble without replacing it, and then drawing a blue marble.A. 1/16 = 0.063B. 4/15=0.267C. 1/4 =0.25D. 35/132=0.265

Respuesta :

Let:

A = Draw a red marble

B = Draw a blue marble

so:

[tex]\begin{gathered} P(A)=\frac{8}{16}=\frac{1}{2} \\ P(B)=\frac{8}{15} \\ so\colon \\ P(A)\cdot P(B)=\frac{1}{2}\cdot\frac{8}{15}=\frac{8}{30}=\frac{4}{15}=0.267 \end{gathered}[/tex]

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