Half-life formula
[tex]N(t)=N_0\cdot(\frac{1}{2})^{\frac{t}{t_{0.5}}}[/tex]where:
• N(t): quantity of the substance remaining
,• N0: initial quantity of the substance
,• t: time elapsed
,• t0.5: half-life of the substance
Substituting with t0.5 = 5.26 years, N0 = 4 g, and t = 3 years, we get:
[tex]\begin{gathered} N(t)=4\cdot(\frac{1}{2})^{\frac{3}{5.26}} \\ N(t)\approx2.7\text{ g} \end{gathered}[/tex]It remains approximately 2.7 g in 3 years
