[tex]\begin{gathered} x=50m \\ t=\text{ 4 s} \\ v_o=0m/s,x_o=0m \\ a=\text{?} \\ x=x_o+v_ot+\text{ }\frac{at^2}{2} \\ x=\frac{at^2}{2} \\ x=\text{ }\frac{at^2}{2} \\ \text{solving a} \\ 2x_{}=at^2 \\ a=\frac{2x}{t^2} \\ a=\frac{2(50m)}{(4s)^2}=\frac{100m}{16s^2}=6.25m/s^2 \\ \text{the }magnitude\text{ of the acceleration is }6.25m/s^2 \end{gathered}[/tex]
