Since BX bisects the angle, then the measure of ABX and XBC must be the same. Then we have the next equation
[tex]\begin{gathered} m\angle ABX=m\angle XBC \\ 5x=3x+10 \\ 5x-3x=10 \\ 2x=10 \\ x=\frac{10}{2} \\ x=5 \end{gathered}[/tex]
Then,
[tex]m\angle XBC=3(5)+10=15+10=25[/tex]
then, the answer is 25
