A)
[tex]\text{slope}=\frac{1}{5}[/tex]
[tex](0,\frac{1}{5})[/tex]
Explanation
f.
[tex]y=\frac{x+1}{5}[/tex]
Step 1
a) get the slope-intercept form
[tex]\begin{gathered} y=mx+b \\ \text{where m is the slope and b is the y-intercept} \end{gathered}[/tex]
so
[tex]\begin{gathered} y=\frac{x+1}{5} \\ y=\frac{x}{5}+\frac{1}{5} \\ y=\frac{1}{5}x+\frac{1}{5} \end{gathered}[/tex]
therefore,
[tex]\begin{gathered} y=\frac{1}{5}x+\frac{1}{5}\rightarrow y=mx+b \\ y=\frac{1}{5} \\ b=\frac{1}{5} \end{gathered}[/tex]
so
the slope is
[tex]\text{slope}=\frac{1}{5}[/tex]
and the y-intercpet is the ordered pair
[tex](0,\frac{1}{5})[/tex]
I hope this helps you
