Explanation
Given that
[tex]\begin{gathered} radius=15 \\ length\text{ of one side=9.3} \end{gathered}[/tex]
First we will find the perimeter of the decagon.
[tex]p=10\times9.3=93[/tex]
We will then find the height of one of the triangles of the decagon
[tex]\begin{gathered} 15^2=h^2+9.3^2 \\ h^2=225-86.49 \\ h=\sqrt{138.51} \\ h=11.769027 \end{gathered}[/tex]
Therefore, the area of the polygon is ten times one of the triangle is
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