Answer
b. 0.30 M
Explanation
The molarity of a solution can be calculated using the molarity formula:
[tex]Molarity=\frac{Moles\text{ }of\text{ }solute}{Volume\text{ }of\text{ }solution\text{ }in\text{ }liters}[/tex]For part b:
75.3 g of sucrose, C₁₂H₂₂O₁₁ needs to be converted to moles of C₁₂H₂₂O₁₁ using the mole formula:
[tex]Moles=\frac{Mass}{Molar\text{ }mass}[/tex]Using the atomic masses of elements in the periodic table, the molar mass of C₁₂H₂₂O₁₁ = (12 x 12) + (1 x 22) + (16 x 11) = 144 + 22 + 176 = 342 g/mol
So mole of C₁₂H₂₂O₁₁ is:
[tex]Moles\text{ }of\text{ }C₁₂H₂₂O₁₁=\frac{75.3g}{342g\text{/}mol}=0.2201754386\text{ }mol[/tex]The volume of solution in liters = (725 mL/1000 mL) x 1 L = 0.725 L
Finally, the molarity of C₁₂H₂₂O₁₁ solution will be:
[tex]Molarity\text{ }of\text{ }C₁₂H₂₂O₁₁=\frac{0.2201754386\text{ }mol}{0.725\text{ }L}=0.30\text{ }M[/tex]Hence, the molarity of C₁₂H₂₂O₁₁ solution is 0.30 M
