Respuesta :

[tex]y+7=(x+3)^2[/tex]

vertex (-3,-7)

Explanation

[tex]f(x)=x^2+6x+2[/tex]

Step 1

prepare to complete the square

[tex]\begin{gathered} y=x^2+6x+2 \\ y+?\text{ = (}x^2+6x+\text{ ?) }+2 \\ \\ \end{gathered}[/tex]

Step 2

add 9 in both sides

[tex]\begin{gathered} y+9=\mleft(x^2+6x+9\mright)+2 \\ y+9=(x+3)^2+2 \end{gathered}[/tex]

Step 3

write in vertex form

[tex]\begin{gathered} y+9=(x+3)^2+2 \\ y+9-2=(x+3)^2 \\ y+7=(x+3)^2 \\ \\ \end{gathered}[/tex]

Step 4

the vertex is

(-3.-7)

I hope this helps you