The equation of a line in slope-intercept form is generally given as;
[tex]y=mx+b[/tex]Where the variables are;
[tex]\begin{gathered} m=\text{slope} \\ b=y-\text{intercept} \\ (x,y)=(8,1) \end{gathered}[/tex]With the slope given as 5/8, we shall substitute the known values into the equation and we'll now have;
[tex]\begin{gathered} y=mx+b \\ 1=\frac{5}{8}(8)+b \\ 1=5+b \\ \text{Subtract 5 from both sides;} \\ -4=b \end{gathered}[/tex]We now have the value of b, and the value of m (already given).
We substitute these into the general equation in slope-intercept form and we have;
[tex]\begin{gathered} y=mx+b \\ y=\frac{5}{8}x+(-4) \\ y=\frac{5}{8}x-4 \end{gathered}[/tex]ANSWER:
The equation of the line is;
[tex]\begin{gathered} y=\frac{5}{8}x-4 \\ OR \\ y=\frac{5x}{8}-4 \end{gathered}[/tex]