Using the scale 1 inch = 5 feet, the dimension of 45 ft is equivalent to:
[tex]\frac{1\text{ in}}{x\text{ in}}=\frac{5\text{ ft}}{45\text{ ft}}[/tex]Solving for x:
[tex]\begin{gathered} 1\cdot45\text{ = 5}\cdot x \\ \frac{45}{5}=x \\ 9\text{ in = x} \end{gathered}[/tex]Similarly, the dimension of 75 ft is equivalent to:
[tex]\begin{gathered} \frac{1\text{ in}}{y\text{ in}}=\frac{5\text{ ft}}{75\text{ ft}} \\ 1\cdot75\text{ = 5}\cdot y \\ \frac{75}{5}=\text{ y} \\ 15\text{ in = y} \end{gathered}[/tex]