we can replace y on the second equation to find x
[tex]\begin{gathered} 3x^2+2(x-1)=4 \\ 3x^2+2x-2=4 \\ 3x^2+2x-6=0 \end{gathered}[/tex]to find X we need to use this formula to factor
[tex]x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}[/tex]where a=3, b=2 and c=-6
so, replace
[tex]\begin{gathered} x=\frac{-(2)\pm\sqrt[]{(2)^2-4(3)(-6)}}{2(3)} \\ \\ x=\frac{-2\pm\sqrt[]{4+72}}{6} \\ \\ x=\frac{-2\pm\sqrt[]{76}}{6} \\ \\ x=\frac{-1\pm\sqrt[]{19}}{3} \end{gathered}[/tex]we have 2 solutions for x
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