In the triangle, the given values are
[tex]\begin{gathered} \theta=37.5^0 \\ \text{opposite}=17 \\ \text{hypotenus}=x \end{gathered}[/tex]
With the values above given, the trigonometric ratio to be used will be
[tex]\begin{gathered} \sin \theta=\frac{opposite}{hypotenus} \\ \sin 37.5^0=\frac{17}{x} \end{gathered}[/tex]
Hence,
The final answer is Sin37.5°= 17/x
