The volume of the pyramid is given by the formula:
[tex]V=\frac{1}{3}s^2h[/tex]
Where:
s = 8m
h = 11m
So, substitute the values:
[tex]V=\frac{1}{3}(8)^2(11)=\frac{1}{3}\cdot64\cdot11=\frac{704}{3}=234.667[/tex]
And round to the nearest tenth is 234.7 m^3
Answer: 234.7 m^3
