A solution is made by dissolving9.68 g of potassium chloride(KCI) in 565 g of water.What is the molality of the solution?[?] m KCIMolar mass of KCI: 74.55 g/mol

Answer
Molality = 0.230 m KCl
Explanation
Given
Mass of solute (potassium chloride) = 9.68 g
Mass of water (solvent) = 565 g = 0.565 kg
Molar mass of KCl = 74.55 g/mol
Required: Molality of the solution
Solution
Step 1: Calculate the moles of the solute
n = m/M where n is the moles, m is the mass and M is the molar mass
n = 9.68g/74.55g/mol
n = 0.130 moles
Step 2: Calculate the molality (Make sure the mass of solvent is in kg)
Molality = moles of the solute/Kg of solvent
Molality = 0.130 mol/0.565kg
Molality = 0.230 mol/kg (or 0.230 m)