Given the function:
[tex]h(c)=\sqrt[4]{-3c+75}[/tex]We will find the value of the function when c = -2
so,
[tex]\begin{gathered} h(-2)=\sqrt[4]{-3\cdot(-2)+75}=\sqrt[4]{6+75}=\sqrt[4]{81}=\sqrt[4]{3^4}=3 \\ \\ h(-2)=3 \end{gathered}[/tex]so, the answer will be h(-2) = 3