EXPLANATION
Let's see the facts:
Velocity of flow = unknown
Rate of flow = 0.75 cfs
Cross-sectional area of the pipe= 8 inches
We need to convert the 8 inches to feet units:
12 inches --> 1 feet
8 inches ---> 8/12 = 2/3 = 0.67 feet
Applying the given equation:
[tex]Velocity_{\text{ }}offlow_{fps}\text{=}\frac{Rate\text{ of flow}}{\text{Cross}-\text{sectional area}}=\frac{0.75\text{cfs}}{2/3\text{ f}eet}=\frac{9}{8}=1.125\text{ fps}[/tex]
Hence, the solution is Velocity of flow= 1.125 fps
