Let us revise some rules of log
[tex]\log (a)+\log (b)=\log (a)(b)[/tex][tex]\log (a)-\log (b)=\log (\frac{a}{b})[/tex]
Let us use these rules to solve the question
The given expression is
[tex]\log (2)-\log (6)[/tex]
By using the 2nd rule
[tex]\log (2)-\log (6)=\log (\frac{2}{6})=\log (\frac{1}{3})[/tex]
Also, we can use the first rule when chang log(6) to -log(1/6)
[tex]\begin{gathered} \log (2)-\log (6)=\log (2)-\lbrack-\log (\frac{1}{6})\rbrack \\ \log (2)-\log (6)=\log (2)+\log (\frac{1}{6}) \end{gathered}[/tex]
By using the first rule
[tex]\log (2)-\log (6)=\log (2)+\log (\frac{1}{6})[/tex]
The correct answers are C and D
