How do I find the surface area of a cylinder rounded to the nearest 10th

In general, the surface area of a cylinder is given by the formula below
[tex]\begin{gathered} A=2\pi rh+2r^2\pi \\ r\to\text{ radius} \\ h\to\text{ height} \end{gathered}[/tex]Therefore, in our case,
[tex]\begin{gathered} r=5,h=11 \\ \Rightarrow A=2\pi\cdot55+2\pi\cdot25 \\ \Rightarrow A=2\pi\cdot80 \\ \Rightarrow A=160\pi \end{gathered}[/tex]Rounding to the nearest tenth,
[tex]\Rightarrow A\approx502.7[/tex]Thus, the surface area is 502.7in^2