Given data:
* The mass of the first object is M_1 = 50 kg.
* The initial velocity of the first object is v_1i = 2 m/s.
* The mass of the second object is M_2 = 50 kg.
* The initial velocity of the second object is v_2i = 0 m/s.
Solution:
The initial momentum of the system is,
[tex]\begin{gathered} p_i=M_1v_{1i}+M_2v_{2i} \\ p_i=50\times2+50\times0 \\ p_i=100+0 \\ p_i=100\text{ kgm/s} \end{gathered}[/tex]
The final momentum of the system is,
[tex]p_f=(M_1+M_2)v_{}[/tex]
where v is the velocity of both the objects as both the objects are stick together after the collision(pure inelastic collision) and moves with the same velocity,
Substituting the known values,
[tex]\begin{gathered} p_f=(50+50)v_{} \\ p_f=100v \end{gathered}[/tex]
According to the law of conservation of momentum,
[tex]\begin{gathered} p_i=p_f \\ 100=100v \\ v=\frac{100}{100} \\ v=1\text{ m/s} \end{gathered}[/tex]
Thus, the final velocity of each object is 1 meter per second.
