For the function
[tex]f(x)=x^2+6x+9[/tex]To calculate its vertex (x-intersect) you have to do as follws using the formula:
[tex]\begin{gathered} x_v=-\frac{b}{2a} \\ \text{For} \\ f(x)=ax^2+bx+c \end{gathered}[/tex]For the given function
a=1
b=6
c=9
So
[tex]x_v=-\frac{6}{2\cdot1}=-\frac{6}{2}=-3[/tex]The coordinates for the bottom of the inside of the glas, i.e. the x-intersect of the parabola are (-3,0)