A right circular cone has a radius of 4x + 5 and a height '2' units less than its radius. Express the volume of the cone as a polynomial function. The volume of a cone is 'V = 1/3 pi r^2 h for radius r and height h.

A right circular cone has a radius of 4x 5 and a height 2 units less than its radius Express the volume of the cone as a polynomial function The volume of a con class=

Respuesta :

Answer:[tex]V=\frac{1}{3}\pi(64x^3+208x^2+220x+75)[/tex]Explanation:

The radius of the cone, r = 4x + 5

The height is 2 units less than the radius

h = 4x + 5 - 2

h = 4x + 3

The volume of the cone is given as:

[tex]V=\frac{1}{3}\pi r^2h[/tex]

Substitute r = 4x + 5 and h = 4x + 3 into the formula for the volume

[tex]\begin{gathered} V=\frac{1}{3}\pi(4x+5)^2(4x+3) \\ V=\frac{1}{3}\pi(16x^2+40x+25)(4x+3) \\ V=\frac{1}{3}\pi(64x^3+48x^2+160x^2+120x+100x+75) \\ V=\frac{1}{3}\pi(64x^3+208x^2+220x+75) \end{gathered}[/tex]

The volume of the cone expressed as a polynomial function is:

[tex]V=\frac{1}{3}\pi(64x^3+208x^2+220x+75)[/tex]