The equation is a linear equation
Let us pick any two points on the table.
When x = -1, y = -1 that is point (-1, -1)
When x = 0, y = 3, that is point(0, 3)
[tex]\begin{gathered} \text{slope,m = }\frac{y_2-y_1}{x_2-x_1} \\ \text{where (}x_1,y_1)\text{ = (-1,-1)} \\ \text{and (x}_2,y_2)=(0,3) \end{gathered}[/tex][tex]\begin{gathered} m=\frac{3-(-1)}{0-(-1)} \\ m=\frac{3+1}{0+1} \\ \\ m=\frac{4}{1} \\ m=4 \end{gathered}[/tex]The eqaution od a straight line can be determined by the equation
[tex]\begin{gathered} y-y_1=m(x-x_1) \\ y-(-1)=4(x-(-1) \\ y+1=4(x+1) \\ y+1=4x+4 \\ y=4x+4-1_{} \\ y=4x+3 \end{gathered}[/tex]Hence, the answer is y= 4x +3. Option A is the answer
