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A 0.80-kg block initially at rest on a frictionless horizontal surface is acted upon by a force of 6.0 N for a distance of 3.0 m. How much kinetic energy does the block gain? answer with:___J

Respuesta :

Given

Mass of the block, m=0.80 kg

The force is F=6.0 N

The distanec travelled, s=3.0 m

To find

The kinetic energy

Explanation

By work energy theorem

Kinetic energy is equal to the work done

Thus,

[tex]\begin{gathered} K=F.s \\ \Rightarrow K=6\times3=18\text{ J} \end{gathered}[/tex]

Conclusion

The kinetic energy is 18 J.

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