To find if the given binomials can be a difference of two squares find if both terms in the binomial have an exact square root, if both terms have a exact square root you can write if as a difference of squares:
[tex]\begin{gathered} 2x^2-4 \\ \sqrt{2x^2}=\sqrt{2}x \\ \sqrt{4}=2 \\ \\ \\ 25x^2-1 \\ \sqrt{25x^2}=5x \\ \sqrt{1}=1 \\ 25x^2-1=(5x)^2-1^2 \\ \\ \\ 16x^2-16 \\ \sqrt{16x^2}=4x \\ \sqrt{16}=4 \\ 16x^2-16=(4x)^2-4^2 \\ \\ \\ x^2-169 \\ \sqrt{x^2}=x \\ \sqrt{169}=13 \\ x^2-169=x^2-13^2 \end{gathered}[/tex]As you can see above the binomial taht cannot be written as a difference of twe squares is: 2x^2-4Answer: first option
