Answer:
sinA = 0.37
cosA = 0.93
tanA = 0.40
secA = 1.08
cscA = 2.69
cot A = 2.50
Explanation:
Given that a = 4, b = 10. To obtain c, we use the Pythagorean theorem:
[tex]\begin{gathered} c^2=a^2+b^2 \\ =4^2+10^2 \\ =116 \\ c=\sqrt{116}=10.77 \end{gathered}[/tex]
Now
[tex]\begin{gathered} \sin A=\frac{Opposite}{hypotenuse}=\frac{a}{c} \\ \\ =\frac{4}{10.77}=0.37 \end{gathered}[/tex][tex]\begin{gathered} \cos A=\frac{adj}{hyp}=\frac{b}{c} \\ \\ =\frac{10}{10.77}=0.93 \end{gathered}[/tex][tex]\begin{gathered} \tan A=\frac{opp}{adj}=\frac{a}{b} \\ \\ =\frac{4}{10}=0.40 \end{gathered}[/tex][tex]secA=\frac{1}{cosA}=\frac{10.77}{10}=1.08[/tex][tex]cscA=\frac{1}{sinA}=\frac{10.77}{4}=2.69[/tex][tex]cotA=\frac{1}{tanA}=\frac{10}{4}=2.50[/tex]
