Given:
[tex]\tan \theta=\frac{1}{7}[/tex]
Opposite side= 1 ; adjacent side=7
[tex]\begin{gathered} \text{hypotenuse}=\sqrt[]{1^2+7^2} \\ \text{hypotenuse}=\sqrt[]{1^{}+49^{}} \\ \text{hypotenuse}=\sqrt[]{50^{}} \\ \text{hypotenuse}=5\sqrt[]{2} \end{gathered}[/tex][tex]\begin{gathered} \sin \theta=\frac{opposite\text{ side}}{hypotenuse\text{ side}}=\frac{1}{5\sqrt[]{2}} \\ \cos \theta=\frac{adjacent\text{ side}}{\text{hypotenuse side}}=\frac{7}{5\sqrt[]{2}} \\ co\sec \theta=\frac{5\sqrt[]{2}}{1}=5\sqrt[]{2} \\ \sec \theta=\frac{5\sqrt[]{2}}{7} \\ \cot \theta=\frac{7}{1}=7 \end{gathered}[/tex]
