Given the length of the radius EG = 15 feet
[tex]Using\text{ the formula of length of an arc is }\frac{\theta}{360}\text{ }\times\text{ 2}\pi\text{r}[/tex]
The angle at the centre is twice the angle at the circumference
[tex]\begin{gathered} [tex]\begin{gathered} \theta\text{ = 2 }\times52^0 \\ \theta=104^0 \\ \text{Therefore }\frac{104}{360}\text{ }\times\text{ 2 }\times\text{ }\frac{22}{7\text{ }}\text{ }\times\text{ 15} \\ =\text{ 27.23 f}eet \end{gathered}[/tex]
Hence the approximate length of EG = 27 feet
