As given by the question
There are given that the equation
[tex]2x^2-5x-2[/tex]Now,
Solve this equation by using quadratic formula
So,
From the quadratic formula:
[tex]x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}[/tex]Then,
[tex]\begin{gathered} x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a} \\ x=\frac{-(-5)\pm\sqrt[]{(-5)^2-4\times2\times(-2)}}{2\times2} \\ x=\frac{5\pm\sqrt[]{25+16}}{4} \\ x=\frac{5\pm\sqrt[]{41}}{4} \end{gathered}[/tex]Hence, the value of the given equation by using the quadratic formula in simplest radical form is shown below:
[tex]x=\frac{5\pm\sqrt[]{41}}{4}[/tex]