Respuesta :

Let us revise the negative exponents

[tex]a^{-n}=\frac{1}{a^n}[/tex]

We will use this rule to solve the question

[tex]2^{-3}=\frac{1}{2^3}[/tex][tex]2^2=2\times2\times2=8[/tex][tex]undefined[/tex]

Otras preguntas