Respuesta :
Answer:24.82%
Explanation:
Let x be a random variable representing the amount the customers spend per transaction. Since the amount is normally distributed, we would calculate the z score by applying the formula,
z = (x - μ)/σ
where
x is the sample mean
μ is the population mean
σ is the population standard deviation
From the information given,
μ = 5800
σ = 900
We want to calculate P(4867 ≤ x ≤ 5568)
For x = 4867,
z = (4867 - 5800)/900 = - 1.04
From the normal distribution table, the probability value corresponding to a z score of
- 1.04 is 0.1492
For x = 5568,
z = (5568- 5800)/900 = - 0.26
From the normal distribution table, the probability value corresponding to a z score of
- 0.26 is 0.3974
Thus,
P(4867 ≤ x ≤ 5568) = 0.3974 - 0.1492 = 0.2482
We would convert to percentage by multiplying by 100
P(4867 ≤ x ≤ 5568) = 0.2482 x 100 = 24.82%
The percentage of customers spend between RS4867 and RS5568 per month is 24.82%
