Respuesta :

Solution

Distance between X and Y

[tex]D_{XY}=\sqrt{(2+5)^2+(-1+4)^2}=\sqrt{58}[/tex]

Distance between Y and Z

[tex]D_{YZ}=\sqrt{(-2+5)^2+(3+4)^2}=\sqrt{58}[/tex]

Since

[tex]D_{XY}=D_{YZ}[/tex]

Hence, the Triangle is Isosceles

Ver imagen JeanetteM70390