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The absolute value function g(x) = |x − 2| − 1 is translated 3 units right and 4 units up to become g'(x). The quadratic function f(x) graphed below is moved 2 units right and 7 units up to become f'(x). Which of these two transformed functions has a range of y ≤ 3, and what is the vertex of this transformed function?

The absolute value function gx x 2 1 is translated 3 units right and 4 units up to become gx The quadratic function fx graphed below is moved 2 units right and class=

Respuesta :

Given: The function of the f(x)

To Determine: The range and the vertex if f(x) is moved 2 units right and 7 units up to become f'(x)

Solution

Please note that the base function is moved to the right by 2 units, then the peak of the curve would be on y = -4, and 7 units up, would take the peak of the curve to y = 3

Hence, the vertex, would be (0, 3) and the range would be y ≤ 3, OPTION D

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