To answer this question, we have here a linear function. We can give the function some values for x that must be integers, and we need that the values for y must be integer too.
Therefore, we have that:
For x = 1
We need to substitute the value of x into the equation, and then the result will be the value for y.
[tex]y=-2(1)-3\Rightarrow y=-2-3\Rightarrow y=-5[/tex]
Therefore, one integer solution is (1, -5).
For x = 2
We can follow the previous procedure as follows:
[tex]y=-2(2)-3\Rightarrow y=-4-3\Rightarrow y=-7[/tex]
Therefore, another solution is (2, -7).
For x = 0
We have:
[tex]y=-2(0)-3\Rightarrow y=-3[/tex]
Therefore, another solution is (0, -3).
In summary, the integer solutions can be (1, -5), (2, -7) and (0, -3).
