A plane rises from take-off andflies at an angle of 18with thehorizontal runway. When it hasgained 200 feet, find thedistance that the plane hasflown.

Answer:
647 ft
Explanation:
Given the below figure;
To determine the value c, we have to take the sine of angle 18 degrees as seen below;
[tex]\begin{gathered} \sin18=\frac{opposit\text{e side to angle 18}}{hypotenuse\text{ to angle 18}}=\frac{200}{c} \\ \sin18=\frac{200}{c} \end{gathered}[/tex]Let's cross multiply;
[tex]c*\sin18=200[/tex]Let's divide both sides by sin 18;
[tex]\begin{gathered} \frac{c*\sin18}{\sin18}=\frac{200}{\sin18} \\ c=\frac{200}{\sin18} \\ c=647ft \end{gathered}[/tex]So the distance the plane has flown is 647 ft