Given:
[tex]arcsin(cos35^{\circ})[/tex]To simplify:
Explanation:
As we know,
[tex]cos\theta=sin(90-\theta)[/tex]Therefore, we write,
[tex]\begin{gathered} arcsin(cos35^{\circ})=arcsin(sin(90^{\circ}-35^{\circ})) \\ =arcsin(sin(55^{\circ}) \\ =55^{\circ} \end{gathered}[/tex]Thus, the answer is 55 degrees.
Fina;
