ANSWER
80 units²
EXPLANATION
One way to solve this is to find the area of the blue square and the subtract the areas of the red triangles:
The blue square is 12 units long by 12 units wide. Its area is:
[tex]A_{\text{square}}=12\times12=144[/tex]
Then, the area of the big triangle, which has a base 12 units long and a height of 10 units, is:
[tex]A_{\text{traingle}1}=\frac{12\times10}{2}=\frac{120}{2}=60[/tex]
The smaller triangle has a base of 4 units and a heigth of 2 units. Its area is:
[tex]A_{\text{triangle}2}=\frac{4\times2}{2}=\frac{8}{2}=4[/tex]
So the total area of the figure is:
[tex]\begin{gathered} A=A_{\text{square}}-A_{triangle1}-A_{triangle2} \\ A=144-60-4 \\ A=80 \end{gathered}[/tex]
