INFORMATION:
We know that:
- there are 2.0L of solution
- the solution has a molarity of 0.50M
And we must find the number of moles of the solute (sodium nitrate)
STEP BY STEP EXPLANATION:
To find it, we need to use the formula of the molarity
[tex]Molarity=\frac{moles\text{ of solute}}{litres\text{ of solution}}[/tex]Is given that,
- Molarity = 0.50M = 0.50 mol/L
- litres of solution = 2.0L
Now, replacing in the formula
[tex]0.50\frac{mol}{L}=\frac{moles\text{ of solute}}{2.0L}[/tex]Finally, solving for the moles of solute
[tex]\begin{gathered} 0.50\frac{mol}{L}\cdot2.0L=moles\text{ of solute} \\ 1.0mol=moles\text{ of solute} \\ moles\text{ of solute}=1.0mol \end{gathered}[/tex]ANSWER:
There is 1.0mol of sodium nitrate in 2.0L of a 0.50M solution
