Given expression : 12 = -4(6x-3)+12
We need to find the value of x
[tex]\begin{gathered} 12=-4(6x-3)+12 \\ \text{Subtract 12 from both side} \\ 12-12=-4(6x-3)+12-12 \\ -4(6x-3)=0 \\ \text{Simplify the brackets} \\ -24x+12=0 \\ -24x=-12 \\ \text{Divide both side by -24} \\ \frac{-24x}{-24}=\frac{-12}{-24} \\ x=\frac{1}{2} \end{gathered}[/tex]So, x = 1/2
