you (mass 40kg) and a friend (mass 50 kg) are standing on frictionless ice at rest. you oush your friend and he slides to the right with a speed of 4 m/s. what is your speed after the push?

Respuesta :

when two objects interact with each other there momentum is unchanged. Therefore,

[tex]m_1v_1=m_2v_2[/tex][tex]\begin{gathered} 40v_1=50\times4_{} \\ 40v_1=200 \\ v_1=\frac{200}{40} \\ v_1=5m\text{ per seconds} \end{gathered}[/tex]