Respuesta :
Answer
The mass (in grams) of oxygen present = 1.79 grams.
Explanation
Given
Volume, V = 3.0 L
Temperature, T = 34 °C = (34 + 273.15 K) = 307.15 K
Pressure, P = 0.472 atm
What to find:
The mass (in grams) of oxygen present.
Step-by-step solution:
Step 1: Calculate the moles of oxygen present.
Using the ideal gas law:
[tex]PV=nRT[/tex]R is the molar gas constant = 0.0820574 L•atm/mol•K.
[tex]\begin{gathered} 0.472\text{ }atm\times3.0\text{ }L=n(0.0820574\text{ }L•atm/mol•K\times307.15\text{ }K) \\ \\ n=\frac{0.472\text{ }atm\times3.0\text{ }L}{0.0820574\text{ }L•atm/mol•K\times307.15\text{ }K} \\ \\ n=0.056\text{ }mol \end{gathered}[/tex]The moles of oxygen present is 0.056 mol.
Step 2: Convert 0.056 mol oxygen to mass in grams.
The molar mass of oxygen gas = 31.998 g/mol
Using the mole formula below, the mass of oxygen can be calculated as follows:
[tex]\begin{gathered} Moles=\frac{Mass}{Molar\text{ }mass} \\ \\ \Rightarrow Mass=Moles\times Molar\text{ }mass \\ \\ Mass=0.056\text{ }mol\times31.998\text{ }g\text{/}mol \\ \\ Mass=1.791888\text{ }g\approx1.79\text{ }grams \end{gathered}[/tex]The mass (in grams) of oxygen present = 1.79 grams.
