As per given by the question,
There are given that a right angle triangle ABC.
And,
AB=8, AC=13.
Then,
For finding the value of x, here uses trigonometry ratio,
So,
[tex]\begin{gathered} \cos x=\frac{AB}{AC} \\ \cos x=\frac{8}{13} \\ x=\cos ^{-1}(\frac{8}{13}) \end{gathered}[/tex]
Now,
[tex]\begin{gathered} x=\cos ^{-1}(\frac{8}{13}) \\ x=51.68^{\circ} \end{gathered}[/tex]
Hence, the value of x is 51.68 degree.
