Answer:
0.124moles
Explanations:
According to the ideal gas equation
PV = nRT
Given the following parameters
Volume V = 347mL = 0.347L
Pressure P = 6680torr = 8.79atm
R = 0.08205Latm/molK
Temperature T = 27 + 273 = 300K
Substitute the given parameters into the formula
[tex]\begin{gathered} n=\frac{PV}{RT} \\ n=\frac{8.79\times0.347}{0.08205\times300} \\ n=\frac{3.05}{24.615} \\ n=0.124moles \end{gathered}[/tex]
Hence the required moles of nitrogen is 0.124moles
