If gas a volume of 509 liters and pressure of 697 atm and the pressure to 789 atm what is the new volume ?

449.65L
2) According to the Boyle's law, the pressure of a given mass of gas is inversely proportional to its volume provided that the temperature is constant.
[tex]\begin{gathered} P\alpha\frac{1}{V} \\ P=\frac{k}{V} \\ k=P_1V_1=P_2V_2 \\ \end{gathered}[/tex]P1 and P2 are the initial and final pressures
V1 and V2 are the initial and final volumes
Given the following parameters
V1 = 509litres
P1 = 697atm
P2 = 789atm
Substitute to determine the new volume V2
[tex]\begin{gathered} V_2=\frac{P_1V_1}{P_2} \\ V_2=\frac{697\times509}{789} \\ V_2=\frac{354773}{789} \\ V_2=449.65L \end{gathered}[/tex]Hence the new volume of the gas is approximately 449.65L